Base | Representation |
---|---|
bin | 1001001000111001000… |
… | …10100001010111100111 |
3 | 1010000111222220010102022 |
4 | 10210130202201113213 |
5 | 20121043411033411 |
6 | 400131014333355 |
7 | 31454332031561 |
oct | 4443442412747 |
9 | 1100458803368 |
10 | 314011424231 |
11 | 11119829874a |
12 | 50a3595a25b |
13 | 237c390a68b |
14 | 112abd50331 |
15 | 827c7ebedb |
hex | 491c8a15e7 |
314011424231 has 2 divisors, whose sum is σ = 314011424232. Its totient is φ = 314011424230.
The previous prime is 314011424201. The next prime is 314011424249. The reversal of 314011424231 is 132424110413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 314011424231 - 210 = 314011423207 is a prime.
It is a super-2 number, since 2×3140114242312 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 314011424231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314011424201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157005712115 + 157005712116.
It is an arithmetic number, because the mean of its divisors is an integer number (157005712116).
Almost surely, 2314011424231 is an apocalyptic number.
314011424231 is a deficient number, since it is larger than the sum of its proper divisors (1).
314011424231 is an equidigital number, since it uses as much as digits as its factorization.
314011424231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 314011424231 its reverse (132424110413), we get a palindrome (446435534644).
The spelling of 314011424231 in words is "three hundred fourteen billion, eleven million, four hundred twenty-four thousand, two hundred thirty-one".
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