Base | Representation |
---|---|
bin | 101101101100011111101… |
… | …001110011010011101011 |
3 | 102010012021121020221002011 |
4 | 231230133221303103223 |
5 | 402422012422121011 |
6 | 10402322130220351 |
7 | 442603616556151 |
oct | 55543751632353 |
9 | 12105247227064 |
10 | 3140152145131 |
11 | 10008050277a1 |
12 | 4286ba7246b7 |
13 | 19a165a922b1 |
14 | abdac80b3d1 |
15 | 56a389ba621 |
hex | 2db1fa734eb |
3140152145131 has 2 divisors, whose sum is σ = 3140152145132. Its totient is φ = 3140152145130.
The previous prime is 3140152145083. The next prime is 3140152145167. The reversal of 3140152145131 is 1315412510413.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3140152145131 - 213 = 3140152136939 is a prime.
It is a super-2 number, since 2×31401521451312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3140152145093 and 3140152145102.
It is not a weakly prime, because it can be changed into another prime (3140152145231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570076072565 + 1570076072566.
It is an arithmetic number, because the mean of its divisors is an integer number (1570076072566).
Almost surely, 23140152145131 is an apocalyptic number.
3140152145131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3140152145131 is an equidigital number, since it uses as much as digits as its factorization.
3140152145131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 3140152145131 its reverse (1315412510413), we get a palindrome (4455564655544).
The spelling of 3140152145131 in words is "three trillion, one hundred forty billion, one hundred fifty-two million, one hundred forty-five thousand, one hundred thirty-one".
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