Base | Representation |
---|---|
bin | 1001001000111010100… |
… | …11101011110100000111 |
3 | 1010000112220010220012201 |
4 | 10210131103223310013 |
5 | 20121110210441241 |
6 | 400132154455331 |
7 | 31454546416501 |
oct | 4443523536407 |
9 | 1100486126181 |
10 | 314024312071 |
11 | 1111a45a0558 |
12 | 50a3a134547 |
13 | 237c64a0812 |
14 | 112ad946d71 |
15 | 827d9e5931 |
hex | 491d4ebd07 |
314024312071 has 2 divisors, whose sum is σ = 314024312072. Its totient is φ = 314024312070.
The previous prime is 314024312059. The next prime is 314024312143. The reversal of 314024312071 is 170213420413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 314024312071 - 211 = 314024310023 is a prime.
It is a super-2 number, since 2×3140243120712 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314024312971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157012156035 + 157012156036.
It is an arithmetic number, because the mean of its divisors is an integer number (157012156036).
Almost surely, 2314024312071 is an apocalyptic number.
314024312071 is a deficient number, since it is larger than the sum of its proper divisors (1).
314024312071 is an equidigital number, since it uses as much as digits as its factorization.
314024312071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 314024312071 its reverse (170213420413), we get a palindrome (484237732484).
The spelling of 314024312071 in words is "three hundred fourteen billion, twenty-four million, three hundred twelve thousand, seventy-one".
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