314040533 has 2 divisors, whose sum is σ = 314040534. Its totient is φ = 314040532.

The previous prime is 314040487. The next prime is 314040547. The reversal of 314040533 is 335040413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 174847729 + 139192804 = 13223^2 + 11798^2 .

It is an emirp because it is prime and its reverse (335040413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314040533 - 2⁸ = 314040277 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 314040499 and 314040508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314040833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157020266 + 157020267.

It is an arithmetic number, because the mean of its divisors is an integer number (157020267).

Almost surely, 2^314040533 is an apocalyptic number.

It is an amenable number.

314040533 is a deficient number, since it is larger than the sum of its proper divisors (1).

314040533 is an equidigital number, since it uses as much as digits as its factorization.

314040533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 314040533 is about 17721.1888145237. The cubic root of 314040533 is about 679.7176834120.

Adding to 314040533 its reverse (335040413), we get a palindrome (649080946).

The spelling of 314040533 in words is "three hundred fourteen million, forty thousand, five hundred thirty-three".