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3140645477 is a prime number
BaseRepresentation
bin1011101100110010…
…0111001001100101
322002212200022122212
42323030213021211
522413001123402
61235350533205
7140554021544
oct27314471145
98085608585
103140645477
1113718a3482
12737967205
133b0889608
1421b17815b
15135ac6952
hexbb327265

3140645477 has 2 divisors, whose sum is σ = 3140645478. Its totient is φ = 3140645476.

The previous prime is 3140645437. The next prime is 3140645503. The reversal of 3140645477 is 7745460413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3100373761 + 40271716 = 55681^2 + 6346^2 .

It is an emirp because it is prime and its reverse (7745460413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3140645477 - 210 = 3140644453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3140645407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570322738 + 1570322739.

It is an arithmetic number, because the mean of its divisors is an integer number (1570322739).

Almost surely, 23140645477 is an apocalyptic number.

It is an amenable number.

3140645477 is a deficient number, since it is larger than the sum of its proper divisors (1).

3140645477 is an equidigital number, since it uses as much as digits as its factorization.

3140645477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 282240, while the sum is 41.

The square root of 3140645477 is about 56041.4621240381. The cubic root of 3140645477 is about 1464.4446833947. Note that the first 3 decimals are identical.

The spelling of 3140645477 in words is "three billion, one hundred forty million, six hundred forty-five thousand, four hundred seventy-seven".