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3141014013253 is a prime number
BaseRepresentation
bin101101101101010011000…
…001100100010101000101
3102010021111200000100212201
4231231103001210111011
5402430244041411003
610402543435114501
7442634153410204
oct55552301442505
912107450010781
103141014013253
111001107584aa6
124288bb2a2a31
1319a2724c752c
14ac05107d23b
1556a894b3b1d
hex2db53064545

3141014013253 has 2 divisors, whose sum is σ = 3141014013254. Its totient is φ = 3141014013252.

The previous prime is 3141014013191. The next prime is 3141014013257. The reversal of 3141014013253 is 3523104101413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2085878282049 + 1055135731204 = 1444257^2 + 1027198^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3141014013253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3141014013257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570507006626 + 1570507006627.

It is an arithmetic number, because the mean of its divisors is an integer number (1570507006627).

Almost surely, 23141014013253 is an apocalyptic number.

It is an amenable number.

3141014013253 is a deficient number, since it is larger than the sum of its proper divisors (1).

3141014013253 is an equidigital number, since it uses as much as digits as its factorization.

3141014013253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 3141014013253 its reverse (3523104101413), we get a palindrome (6664118114666).

The spelling of 3141014013253 in words is "three trillion, one hundred forty-one billion, fourteen million, thirteen thousand, two hundred fifty-three".