314104013 has 2 divisors, whose sum is σ = 314104014. Its totient is φ = 314104012.

The previous prime is 314104003. The next prime is 314104027. The reversal of 314104013 is 310401413.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 179613604 + 134490409 = 13402^2 + 11597^2 .

It is a cyclic number.

It is not a de Polignac number, because 314104013 - 2¹² = 314099917 is a prime.

It is a super-2 number, since 2×314104013² = 197322661965408338, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 314103982 and 314104000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314104003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157052006 + 157052007.

It is an arithmetic number, because the mean of its divisors is an integer number (157052007).

Almost surely, 2^314104013 is an apocalyptic number.

It is an amenable number.

314104013 is a deficient number, since it is larger than the sum of its proper divisors (1).

314104013 is an equidigital number, since it uses as much as digits as its factorization.

314104013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 314104013 is about 17722.9798002480. The cubic root of 314104013 is about 679.7634795932.

Adding to 314104013 its reverse (310401413), we get a palindrome (624505426).

The spelling of 314104013 in words is "three hundred fourteen million, one hundred four thousand, thirteen".