Base | Representation |
---|---|
bin | 11101010000001111… |
… | …111010111101100011 |
3 | 10000002002120022212121 |
4 | 131100033322331203 |
5 | 1003312221401034 |
6 | 22232521205111 |
7 | 2161253063134 |
oct | 352017727543 |
9 | 100062508777 |
10 | 31411122019 |
11 | 12359839982 |
12 | 6107630797 |
13 | 2c67839044 |
14 | 173da13c8b |
15 | c3c9691b4 |
hex | 7503faf63 |
31411122019 has 2 divisors, whose sum is σ = 31411122020. Its totient is φ = 31411122018.
The previous prime is 31411121977. The next prime is 31411122023. The reversal of 31411122019 is 91022111413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31411122019 - 27 = 31411121891 is a prime.
It is a super-2 number, since 2×314111220192 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31411121984 and 31411122002.
It is not a weakly prime, because it can be changed into another prime (31411122059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15705561009 + 15705561010.
It is an arithmetic number, because the mean of its divisors is an integer number (15705561010).
Almost surely, 231411122019 is an apocalyptic number.
31411122019 is a deficient number, since it is larger than the sum of its proper divisors (1).
31411122019 is an equidigital number, since it uses as much as digits as its factorization.
31411122019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 31411122019 in words is "thirty-one billion, four hundred eleven million, one hundred twenty-two thousand, nineteen".
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