Base | Representation |
---|---|
bin | 100011101101011110110111… |
… | …1111101010100110110011010 |
3 | 1112012012000221110012110010220 |
4 | 1013122331233331110312122 |
5 | 312132422102223240442 |
6 | 3032022042252220510 |
7 | 123110003315200002 |
oct | 10732755775246632 |
9 | 1465160843173126 |
10 | 314114311540122 |
11 | 910a5149a15115 |
12 | 2b29155b46a736 |
13 | 10636b10b85a22 |
14 | 577d2dc937002 |
15 | 264ac7a117eec |
hex | 11daf6ff54d9a |
314114311540122 has 32 divisors (see below), whose sum is σ = 636304180184640. Its totient is φ = 103367126952960.
The previous prime is 314114311540097. The next prime is 314114311540153. The reversal of 314114311540122 is 221045113411413.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1035176097 + ... + 1035479492.
It is an arithmetic number, because the mean of its divisors is an integer number (19884505630770).
Almost surely, 2314114311540122 is an apocalyptic number.
314114311540122 is an abundant number, since it is smaller than the sum of its proper divisors (322189868644518).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
314114311540122 is a wasteful number, since it uses less digits than its factorization.
314114311540122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2070655918.
The product of its (nonzero) digits is 11520, while the sum is 33.
Adding to 314114311540122 its reverse (221045113411413), we get a palindrome (535159424951535).
The spelling of 314114311540122 in words is "three hundred fourteen trillion, one hundred fourteen billion, three hundred eleven million, five hundred forty thousand, one hundred twenty-two".
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