Base | Representation |
---|---|
bin | 1001001001000110011… |
… | …00111010101001001101 |
3 | 1010000210210012222110101 |
4 | 10210203030322221031 |
5 | 20121311014413401 |
6 | 400150050211101 |
7 | 31460160103633 |
oct | 4444314725115 |
9 | 1100723188411 |
10 | 314123201101 |
11 | 1112453a3326 |
12 | 50a67283a91 |
13 | 23810b15738 |
14 | 112bcb29353 |
15 | 828752b101 |
hex | 492333aa4d |
314123201101 has 2 divisors, whose sum is σ = 314123201102. Its totient is φ = 314123201100.
The previous prime is 314123201071. The next prime is 314123201113. The reversal of 314123201101 is 101102321413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 171918036900 + 142205164201 = 414630^2 + 377101^2 .
It is a cyclic number.
It is not a de Polignac number, because 314123201101 - 225 = 314089646669 is a prime.
It is a super-2 number, since 2×3141232011012 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314123201141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157061600550 + 157061600551.
It is an arithmetic number, because the mean of its divisors is an integer number (157061600551).
Almost surely, 2314123201101 is an apocalyptic number.
It is an amenable number.
314123201101 is a deficient number, since it is larger than the sum of its proper divisors (1).
314123201101 is an equidigital number, since it uses as much as digits as its factorization.
314123201101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 314123201101 its reverse (101102321413), we get a palindrome (415225522514).
The spelling of 314123201101 in words is "three hundred fourteen billion, one hundred twenty-three million, two hundred one thousand, one hundred one".
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