Base | Representation |
---|---|
bin | 1110010010010001010111… |
… | …01001001010011111010111 |
3 | 11010020011100020122000011101 |
4 | 13021020223221022133113 |
5 | 13104142110442422403 |
6 | 150451240543050531 |
7 | 6421411152601414 |
oct | 711105351123727 |
9 | 133204306560141 |
10 | 31414123014103 |
11 | a011722527925 |
12 | 36343262a0a47 |
13 | 146b453c95aab |
14 | 7a864753110b |
15 | 397247c6a71d |
hex | 1c922ba4a7d7 |
31414123014103 has 2 divisors, whose sum is σ = 31414123014104. Its totient is φ = 31414123014102.
The previous prime is 31414123014067. The next prime is 31414123014107. The reversal of 31414123014103 is 30141032141413.
It is a strong prime.
It is an emirp because it is prime and its reverse (30141032141413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31414123014103 - 225 = 31414089459671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31414123014107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15707061507051 + 15707061507052.
It is an arithmetic number, because the mean of its divisors is an integer number (15707061507052).
Almost surely, 231414123014103 is an apocalyptic number.
31414123014103 is a deficient number, since it is larger than the sum of its proper divisors (1).
31414123014103 is an equidigital number, since it uses as much as digits as its factorization.
31414123014103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 31414123014103 its reverse (30141032141413), we get a palindrome (61555155155516).
The spelling of 31414123014103 in words is "thirty-one trillion, four hundred fourteen billion, one hundred twenty-three million, fourteen thousand, one hundred three".
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