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3141435214433 is a prime number
BaseRepresentation
bin101101101101101100001…
…000010100101001100001
3102010022121000120121021102
4231231230020110221201
5402432124403330213
610403053323004145
7442650456513035
oct55555410245141
912108530517242
103141435214433
11100130331074a
124289b8369655
1319a30b84cbb9
14ac090da21c5
1556ab1464158
hex2db6c214a61

3141435214433 has 2 divisors, whose sum is σ = 3141435214434. Its totient is φ = 3141435214432.

The previous prime is 3141435214429. The next prime is 3141435214441. The reversal of 3141435214433 is 3344125341413.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2365957719889 + 775477494544 = 1538167^2 + 880612^2 .

It is an emirp because it is prime and its reverse (3344125341413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3141435214433 - 22 = 3141435214429 is a prime.

It is a super-2 number, since 2×31414352144332 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3141435274433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570717607216 + 1570717607217.

It is an arithmetic number, because the mean of its divisors is an integer number (1570717607217).

Almost surely, 23141435214433 is an apocalyptic number.

It is an amenable number.

3141435214433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3141435214433 is an equidigital number, since it uses as much as digits as its factorization.

3141435214433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 207360, while the sum is 38.

The spelling of 3141435214433 in words is "three trillion, one hundred forty-one billion, four hundred thirty-five million, two hundred fourteen thousand, four hundred thirty-three".