Base | Representation |
---|---|
bin | 100011101101110000011101… |
… | …0001101011101101100010100 |
3 | 1112012022122101112001212012020 |
4 | 1013123200322031131230110 |
5 | 312134031412003203034 |
6 | 3032051244401253140 |
7 | 123112511006130540 |
oct | 10733407215355424 |
9 | 1465278345055166 |
10 | 314152064506644 |
11 | 9110a1625396a1 |
12 | 2b2989369341b0 |
13 | 1063a549549880 |
14 | 5781080902a20 |
15 | 264bc396e2249 |
hex | 11db83a35db14 |
314152064506644 has 48 divisors (see below), whose sum is σ = 902180287817088. Its totient is φ = 82853291737728.
The previous prime is 314152064506603. The next prime is 314152064506663. The reversal of 314152064506644 is 446605460251413.
It is a super-2 number, since 2×3141520645066442 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 143842519287 + ... + 143842521470.
It is an arithmetic number, because the mean of its divisors is an integer number (18795422662856).
Almost surely, 2314152064506644 is an apocalyptic number.
It is an amenable number.
314152064506644 is an abundant number, since it is smaller than the sum of its proper divisors (588028223310444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
314152064506644 is a wasteful number, since it uses less digits than its factorization.
314152064506644 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 287685040784 (or 287685040782 counting only the distinct ones).
The product of its (nonzero) digits is 8294400, while the sum is 51.
The spelling of 314152064506644 in words is "three hundred fourteen trillion, one hundred fifty-two billion, sixty-four million, five hundred six thousand, six hundred forty-four".
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