Base | Representation |
---|---|
bin | 101101101110010010001… |
… | …110001100010011001111 |
3 | 102010101020120002212110021 |
4 | 231232102032030103033 |
5 | 402434432004143221 |
6 | 10403240552323011 |
7 | 443002346526211 |
oct | 55562216142317 |
9 | 12111216085407 |
10 | 3142074287311 |
11 | 1001601026653 |
12 | 428b563a3467 |
13 | 19a3b107932b |
14 | ac111bda5b1 |
15 | 56aec5ee041 |
hex | 2db9238c4cf |
3142074287311 has 2 divisors, whose sum is σ = 3142074287312. Its totient is φ = 3142074287310.
The previous prime is 3142074287291. The next prime is 3142074287483. The reversal of 3142074287311 is 1137824702413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3142074287311 - 213 = 3142074279119 is a prime.
It is a super-2 number, since 2×31420742873112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3142074282311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571037143655 + 1571037143656.
It is an arithmetic number, because the mean of its divisors is an integer number (1571037143656).
Almost surely, 23142074287311 is an apocalyptic number.
3142074287311 is a deficient number, since it is larger than the sum of its proper divisors (1).
3142074287311 is an equidigital number, since it uses as much as digits as its factorization.
3142074287311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 225792, while the sum is 43.
Adding to 3142074287311 its reverse (1137824702413), we get a palindrome (4279898989724).
The spelling of 3142074287311 in words is "three trillion, one hundred forty-two billion, seventy-four million, two hundred eighty-seven thousand, three hundred eleven".
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