Base | Representation |
---|---|
bin | 1110010010100010100010… |
… | …10010000010100011101111 |
3 | 11010021001010220100000110222 |
4 | 13021101101102002203233 |
5 | 13104320002132433403 |
6 | 150455403553521555 |
7 | 6422155524346055 |
oct | 711212122024357 |
9 | 133231126300428 |
10 | 31423344421103 |
11 | a0156247a2448 |
12 | 363607a5732bb |
13 | 146c29358703b |
14 | 7a8c800dc1d5 |
15 | 3975d75ce338 |
hex | 1c94514828ef |
31423344421103 has 2 divisors, whose sum is σ = 31423344421104. Its totient is φ = 31423344421102.
The previous prime is 31423344421099. The next prime is 31423344421169. The reversal of 31423344421103 is 30112444332413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31423344421103 - 22 = 31423344421099 is a prime.
It is a super-3 number, since 3×314233444211033 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31423344421003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15711672210551 + 15711672210552.
It is an arithmetic number, because the mean of its divisors is an integer number (15711672210552).
Almost surely, 231423344421103 is an apocalyptic number.
31423344421103 is a deficient number, since it is larger than the sum of its proper divisors (1).
31423344421103 is an equidigital number, since it uses as much as digits as its factorization.
31423344421103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 31423344421103 its reverse (30112444332413), we get a palindrome (61535788753516).
The spelling of 31423344421103 in words is "thirty-one trillion, four hundred twenty-three billion, three hundred forty-four million, four hundred twenty-one thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •