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31426558797031 is a prime number
BaseRepresentation
bin1110010010101000100001…
…10111111010010011100111
311010021100102220202020022021
413021110100313322103213
513104343043023001111
6150501054541044011
76422331265162336
oct711242067722347
9133240386666267
1031426558797031
11a016a24174682
123636816b56607
13146c6864ba128
147a90a6d89d1d
153977248bbd71
hex1c9510dfa4e7

31426558797031 has 2 divisors, whose sum is σ = 31426558797032. Its totient is φ = 31426558797030.

The previous prime is 31426558796977. The next prime is 31426558797041. The reversal of 31426558797031 is 13079785562413.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31426558797031 - 225 = 31426525242599 is a prime.

It is a super-2 number, since 2×314265587970312 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31426558797041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15713279398515 + 15713279398516.

It is an arithmetic number, because the mean of its divisors is an integer number (15713279398516).

It is a 2-persistent number, because it is pandigital, and so is 2⋅31426558797031 = 62853117594062, but 3⋅31426558797031 = 94279676391093 is not.

Almost surely, 231426558797031 is an apocalyptic number.

31426558797031 is a deficient number, since it is larger than the sum of its proper divisors (1).

31426558797031 is an equidigital number, since it uses as much as digits as its factorization.

31426558797031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38102400, while the sum is 61.

The spelling of 31426558797031 in words is "thirty-one trillion, four hundred twenty-six billion, five hundred fifty-eight million, seven hundred ninety-seven thousand, thirty-one".