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314317084181 is a prime number
BaseRepresentation
bin1001001001011101100…
…00100001011000010101
31010001022022001021001012
410210232300201120111
520122210133143211
6400221213542005
731465033063502
oct4445660413025
91101268037035
10314317084181
11111334888581
1250b001a4905
132384203a759
14112da7984a9
158299577d8b
hex492ec21615

314317084181 has 2 divisors, whose sum is σ = 314317084182. Its totient is φ = 314317084180.

The previous prime is 314317084177. The next prime is 314317084313. The reversal of 314317084181 is 181480713413.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 277166449156 + 37150635025 = 526466^2 + 192745^2 .

It is an emirp because it is prime and its reverse (181480713413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314317084181 - 22 = 314317084177 is a prime.

It is a super-2 number, since 2×3143170841812 (a number of 24 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314317084171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157158542090 + 157158542091.

It is an arithmetic number, because the mean of its divisors is an integer number (157158542091).

Almost surely, 2314317084181 is an apocalyptic number.

It is an amenable number.

314317084181 is a deficient number, since it is larger than the sum of its proper divisors (1).

314317084181 is an equidigital number, since it uses as much as digits as its factorization.

314317084181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 41.

Adding to 314317084181 its reverse (181480713413), we get a palindrome (495797797594).

The spelling of 314317084181 in words is "three hundred fourteen billion, three hundred seventeen million, eighty-four thousand, one hundred eighty-one".