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31433012359193 is a prime number
BaseRepresentation
bin1110010010110100100011…
…00010010011000000011001
311010021222002200021011022002
413021122101202103000121
513104444302130443233
6150504043155210345
76422650230434354
oct711322142230031
9133258080234262
1031433012359193
11a019736024425
123637b182a69b5
13147017452c073
147a951a10329b
153979a12486e8
hex1c9691893019

31433012359193 has 2 divisors, whose sum is σ = 31433012359194. Its totient is φ = 31433012359192.

The previous prime is 31433012359139. The next prime is 31433012359211. The reversal of 31433012359193 is 39195321033413.

Together with previous prime (31433012359139) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17695374188569 + 13737638170624 = 4206587^2 + 3706432^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31433012359193 is a prime.

It is a super-2 number, since 2×314330123591932 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (31433012359093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15716506179596 + 15716506179597.

It is an arithmetic number, because the mean of its divisors is an integer number (15716506179597).

Almost surely, 231433012359193 is an apocalyptic number.

It is an amenable number.

31433012359193 is a deficient number, since it is larger than the sum of its proper divisors (1).

31433012359193 is an equidigital number, since it uses as much as digits as its factorization.

31433012359193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 787320, while the sum is 47.

The spelling of 31433012359193 in words is "thirty-one trillion, four hundred thirty-three billion, twelve million, three hundred fifty-nine thousand, one hundred ninety-three".