Base | Representation |
---|---|
bin | 1001001001011111010… |
… | …01011010111011111101 |
3 | 1010001100100010001200211 |
4 | 10210233221122323331 |
5 | 20122222442444442 |
6 | 400222505352421 |
7 | 31465303626031 |
oct | 4445751327375 |
9 | 1101310101624 |
10 | 314331999997 |
11 | 111342245aa4 |
12 | 50b05198711 |
13 | 23845160992 |
14 | 112dc75c1c1 |
15 | 829aa22617 |
hex | 492fa5aefd |
314331999997 has 2 divisors, whose sum is σ = 314331999998. Its totient is φ = 314331999996.
The previous prime is 314331999901. The next prime is 314332000043. The reversal of 314331999997 is 799999133413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 171670177561 + 142661822436 = 414331^2 + 377706^2 .
It is a cyclic number.
It is not a de Polignac number, because 314331999997 - 27 = 314331999869 is a prime.
It is a super-2 number, since 2×3143319999972 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314331991997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157165999998 + 157165999999.
It is an arithmetic number, because the mean of its divisors is an integer number (157165999999).
Almost surely, 2314331999997 is an apocalyptic number.
It is an amenable number.
314331999997 is a deficient number, since it is larger than the sum of its proper divisors (1).
314331999997 is an equidigital number, since it uses as much as digits as its factorization.
314331999997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 44641044, while the sum is 67.
The spelling of 314331999997 in words is "three hundred fourteen billion, three hundred thirty-one million, nine hundred ninety-nine thousand, nine hundred ninety-seven".
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