3143402147 has 2 divisors, whose sum is σ = 3143402148. Its totient is φ = 3143402146.

The previous prime is 3143402113. The next prime is 3143402149. The reversal of 3143402147 is 7412043413.

3143402147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3143402147 - 2¹⁰ = 3143401123 is a prime.

Together with 3143402149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3143402149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571701073 + 1571701074.

It is an arithmetic number, because the mean of its divisors is an integer number (1571701074).

Almost surely, 2^3143402147 is an apocalyptic number.

3143402147 is a deficient number, since it is larger than the sum of its proper divisors (1).

3143402147 is an equidigital number, since it uses as much as digits as its factorization.

3143402147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 29.

The square root of 3143402147 is about 56066.0516444666. The cubic root of 3143402147 is about 1464.8730252953.

The spelling of 3143402147 in words is "three billion, one hundred forty-three million, four hundred two thousand, one hundred forty-seven".