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314342407 is a prime number
BaseRepresentation
bin10010101111000…
…111110000000111
3210220111020201101
4102233013300013
51120432424112
651105240531
710534603111
oct2257076007
9726436641
10314342407
11151490115
1289333147
1350180032
142da683b1
151c8e3757
hex12bc7c07

314342407 has 2 divisors, whose sum is σ = 314342408. Its totient is φ = 314342406.

The previous prime is 314342389. The next prime is 314342411. The reversal of 314342407 is 704243413.

It is a strong prime.

It is an emirp because it is prime and its reverse (704243413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314342407 - 27 = 314342279 is a prime.

It is a super-2 number, since 2×3143424072 = 197622297677107298, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314342447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157171203 + 157171204.

It is an arithmetic number, because the mean of its divisors is an integer number (157171204).

Almost surely, 2314342407 is an apocalyptic number.

314342407 is a deficient number, since it is larger than the sum of its proper divisors (1).

314342407 is an equidigital number, since it uses as much as digits as its factorization.

314342407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 28.

The square root of 314342407 is about 17729.7040866451. The cubic root of 314342407 is about 679.9354083688.

The spelling of 314342407 in words is "three hundred fourteen million, three hundred forty-two thousand, four hundred seven".