314344314401321 has 2 divisors, whose sum is σ = 314344314401322. Its totient is φ = 314344314401320.

The previous prime is 314344314401233. The next prime is 314344314401401. The reversal of 314344314401321 is 123104413443413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 216527546265625 + 97816768135696 = 14714875^2 + 9890236^2 .

It is an emirp because it is prime and its reverse (123104413443413) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-314344314401321 is a prime.

It is not a weakly prime, because it can be changed into another prime (314344314403321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157172157200660 + 157172157200661.

It is an arithmetic number, because the mean of its divisors is an integer number (157172157200661).

Almost surely, 2^{314344314401321} is an apocalyptic number.

It is an amenable number.

314344314401321 is a deficient number, since it is larger than the sum of its proper divisors (1).

314344314401321 is an equidigital number, since it uses as much as digits as its factorization.

314344314401321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 38.

Adding to 314344314401321 its reverse (123104413443413), we get a palindrome (437448727844734).

The spelling of 314344314401321 in words is "three hundred fourteen trillion, three hundred forty-four billion, three hundred fourteen million, four hundred one thousand, three hundred twenty-one".