Base | Representation |
---|---|
bin | 1110010010111000011110… |
… | …10101110010101001010011 |
3 | 11010022011112202211100002001 |
4 | 13021130033111302221103 |
5 | 13110013112442311011 |
6 | 150505032433534431 |
7 | 6423053436611551 |
oct | 711341725625123 |
9 | 133264482740061 |
10 | 31435123010131 |
11 | a01a619477745 |
12 | 3638407114417 |
13 | 147041c8a8b49 |
14 | 7a967a562bd1 |
15 | 397a766b67c1 |
hex | 1c970f572a53 |
31435123010131 has 2 divisors, whose sum is σ = 31435123010132. Its totient is φ = 31435123010130.
The previous prime is 31435123010047. The next prime is 31435123010149. The reversal of 31435123010131 is 13101032153413.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31435123010131 is a prime.
It is a super-2 number, since 2×314351230101312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 31435123010131.
It is not a weakly prime, because it can be changed into another prime (31435123010191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15717561505065 + 15717561505066.
It is an arithmetic number, because the mean of its divisors is an integer number (15717561505066).
Almost surely, 231435123010131 is an apocalyptic number.
31435123010131 is a deficient number, since it is larger than the sum of its proper divisors (1).
31435123010131 is an equidigital number, since it uses as much as digits as its factorization.
31435123010131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 28.
Adding to 31435123010131 its reverse (13101032153413), we get a palindrome (44536155163544).
The spelling of 31435123010131 in words is "thirty-one trillion, four hundred thirty-five billion, one hundred twenty-three million, ten thousand, one hundred thirty-one".
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