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314389343417 is a prime number
BaseRepresentation
bin1001001001100110001…
…00001010110010111001
31010001111100000102002012
410210303010022302321
520122332132442132
6400232314415305
731466601220022
oct4446304126271
91101440012065
10314389343417
11111371651a56
1250b20431535
1323853cba6b6
1411306207c49
1582a0a9d0b2
hex493310acb9

314389343417 has 2 divisors, whose sum is σ = 314389343418. Its totient is φ = 314389343416.

The previous prime is 314389343369. The next prime is 314389343531. The reversal of 314389343417 is 714343983413.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 219941302441 + 94448040976 = 468979^2 + 307324^2 .

It is an emirp because it is prime and its reverse (714343983413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314389343417 - 28 = 314389343161 is a prime.

It is a super-2 number, since 2×3143893434172 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (314389343717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157194671708 + 157194671709.

It is an arithmetic number, because the mean of its divisors is an integer number (157194671709).

Almost surely, 2314389343417 is an apocalyptic number.

It is an amenable number.

314389343417 is a deficient number, since it is larger than the sum of its proper divisors (1).

314389343417 is an equidigital number, since it uses as much as digits as its factorization.

314389343417 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2612736, while the sum is 50.

The spelling of 314389343417 in words is "three hundred fourteen billion, three hundred eighty-nine million, three hundred forty-three thousand, four hundred seventeen".