Base | Representation |
---|---|
bin | 1110010011000001110011… |
… | …00000000100010000001111 |
3 | 11010022122110101112201001001 |
4 | 13021200321200010100033 |
5 | 13110103334040022223 |
6 | 150511221050401131 |
7 | 6423321420523204 |
oct | 711407140042017 |
9 | 133278411481031 |
10 | 31440125314063 |
11 | a021756108724 |
12 | 36393824301a7 |
13 | 1470a390632bb |
14 | 7a99d2a63cab |
15 | 397c6a9259ad |
hex | 1c983980440f |
31440125314063 has 2 divisors, whose sum is σ = 31440125314064. Its totient is φ = 31440125314062.
The previous prime is 31440125314051. The next prime is 31440125314067. The reversal of 31440125314063 is 36041352104413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31440125314063 - 221 = 31440123216911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31440125314067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15720062657031 + 15720062657032.
It is an arithmetic number, because the mean of its divisors is an integer number (15720062657032).
Almost surely, 231440125314063 is an apocalyptic number.
31440125314063 is a deficient number, since it is larger than the sum of its proper divisors (1).
31440125314063 is an equidigital number, since it uses as much as digits as its factorization.
31440125314063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 31440125314063 its reverse (36041352104413), we get a palindrome (67481477418476).
The spelling of 31440125314063 in words is "thirty-one trillion, four hundred forty billion, one hundred twenty-five million, three hundred fourteen thousand, sixty-three".
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