314401331 has 2 divisors, whose sum is σ = 314401332. Its totient is φ = 314401330.

The previous prime is 314401273. The next prime is 314401333. The reversal of 314401331 is 133104413.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-314401331 is a prime.

It is a super-2 number, since 2×314401331² = 197696393869143122, which contains 22 as substring.

Together with 314401333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (314401333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157200665 + 157200666.

It is an arithmetic number, because the mean of its divisors is an integer number (157200666).

Almost surely, 2^314401331 is an apocalyptic number.

314401331 is a deficient number, since it is larger than the sum of its proper divisors (1).

314401331 is an equidigital number, since it uses as much as digits as its factorization.

314401331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 314401331 is about 17731.3657398408. The cubic root of 314401331 is about 679.9778907171.

Adding to 314401331 its reverse (133104413), we get a palindrome (447505744).

The spelling of 314401331 in words is "three hundred fourteen million, four hundred one thousand, three hundred thirty-one".