Base | Representation |
---|---|
bin | 1110010011000011100111… |
… | …10101100000000101100111 |
3 | 11010022201222121010200200211 |
4 | 13021201303311200011213 |
5 | 13110112340111332443 |
6 | 150511502131320251 |
7 | 6423354603361645 |
oct | 711416365400547 |
9 | 133281877120624 |
10 | 31441104011623 |
11 | a022108601689 |
12 | 36395b6150087 |
13 | 1470b63a52297 |
14 | 7a9a86a28195 |
15 | 397cc67ea19d |
hex | 1c9873d60167 |
31441104011623 has 2 divisors, whose sum is σ = 31441104011624. Its totient is φ = 31441104011622.
The previous prime is 31441104011617. The next prime is 31441104011633. The reversal of 31441104011623 is 32611040114413.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31441104011623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31441104011633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15720552005811 + 15720552005812.
It is an arithmetic number, because the mean of its divisors is an integer number (15720552005812).
Almost surely, 231441104011623 is an apocalyptic number.
31441104011623 is a deficient number, since it is larger than the sum of its proper divisors (1).
31441104011623 is an equidigital number, since it uses as much as digits as its factorization.
31441104011623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 31441104011623 in words is "thirty-one trillion, four hundred forty-one billion, one hundred four million, eleven thousand, six hundred twenty-three".
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