Base | Representation |
---|---|
bin | 101101110000010011100… |
… | …000011110001110101001 |
3 | 102010120211201120011122111 |
4 | 231300103200132032221 |
5 | 403003402243341301 |
6 | 10404240114522321 |
7 | 443110165263445 |
oct | 55602340361651 |
9 | 12116751504574 |
10 | 3144243340201 |
11 | 1002514439147 |
12 | 4294608963a1 |
13 | 19a668563892 |
14 | ac279cdd825 |
15 | 56bc7c56551 |
hex | 2dc1381e3a9 |
3144243340201 has 2 divisors, whose sum is σ = 3144243340202. Its totient is φ = 3144243340200.
The previous prime is 3144243340193. The next prime is 3144243340241. The reversal of 3144243340201 is 1020433424413.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1655596890000 + 1488646450201 = 1286700^2 + 1220101^2 .
It is a cyclic number.
It is not a de Polignac number, because 3144243340201 - 23 = 3144243340193 is a prime.
It is not a weakly prime, because it can be changed into another prime (3144243340241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572121670100 + 1572121670101.
It is an arithmetic number, because the mean of its divisors is an integer number (1572121670101).
Almost surely, 23144243340201 is an apocalyptic number.
It is an amenable number.
3144243340201 is a deficient number, since it is larger than the sum of its proper divisors (1).
3144243340201 is an equidigital number, since it uses as much as digits as its factorization.
3144243340201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 3144243340201 its reverse (1020433424413), we get a palindrome (4164676764614).
The spelling of 3144243340201 in words is "three trillion, one hundred forty-four billion, two hundred forty-three million, three hundred forty thousand, two hundred one".
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