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3144243340241 is a prime number
BaseRepresentation
bin101101110000010011100…
…000011110001111010001
3102010120211201120011200222
4231300103200132033101
5403003402243341431
610404240114522425
7443110165263533
oct55602340361721
912116751504628
103144243340241
111002514439183
12429460896415
1319a6685638c3
14ac279cdd853
1556bc7c5657b
hex2dc1381e3d1

3144243340241 has 2 divisors, whose sum is σ = 3144243340242. Its totient is φ = 3144243340240.

The previous prime is 3144243340201. The next prime is 3144243340307. The reversal of 3144243340241 is 1420433424413.

3144243340241 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3128936454400 + 15306885841 = 1768880^2 + 123721^2 .

It is a cyclic number.

It is not a de Polignac number, because 3144243340241 - 210 = 3144243339217 is a prime.

It is not a weakly prime, because it can be changed into another prime (3144243340201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572121670120 + 1572121670121.

It is an arithmetic number, because the mean of its divisors is an integer number (1572121670121).

Almost surely, 23144243340241 is an apocalyptic number.

It is an amenable number.

3144243340241 is a deficient number, since it is larger than the sum of its proper divisors (1).

3144243340241 is an equidigital number, since it uses as much as digits as its factorization.

3144243340241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 3144243340241 its reverse (1420433424413), we get a palindrome (4564676764654).

The spelling of 3144243340241 in words is "three trillion, one hundred forty-four billion, two hundred forty-three million, three hundred forty thousand, two hundred forty-one".