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3144314111 is a prime number
BaseRepresentation
bin1011101101101010…
…0110110011111111
322010010120201002012
42323122212303333
522414421022421
61240001321435
7140630141351
oct27332466377
98103521065
103144314111
111373979804
1273903627b
133b15723c3
1421b8510d1
1513609d95b
hexbb6a6cff

3144314111 has 2 divisors, whose sum is σ = 3144314112. Its totient is φ = 3144314110.

The previous prime is 3144314077. The next prime is 3144314141. The reversal of 3144314111 is 1114134413.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3144314111 is a prime.

It is a super-2 number, since 2×31443141112 = 19773422457267440642, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3144314141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572157055 + 1572157056.

It is an arithmetic number, because the mean of its divisors is an integer number (1572157056).

Almost surely, 23144314111 is an apocalyptic number.

3144314111 is a deficient number, since it is larger than the sum of its proper divisors (1).

3144314111 is an equidigital number, since it uses as much as digits as its factorization.

3144314111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 576, while the sum is 23.

The square root of 3144314111 is about 56074.1839976294. The cubic root of 3144314111 is about 1465.0146746114.

Adding to 3144314111 its reverse (1114134413), we get a palindrome (4258448524).

It can be divided in two parts, 31443 and 14111, that added together give a palindrome (45554).

The spelling of 3144314111 in words is "three billion, one hundred forty-four million, three hundred fourteen thousand, one hundred eleven".