Base | Representation |
---|---|
bin | 1001001001101011001… |
… | …10111011111101000111 |
3 | 1010001121022022012111220 |
4 | 10210311212323331013 |
5 | 20122424043341403 |
6 | 400240441131423 |
7 | 31500630001356 |
oct | 4446546737507 |
9 | 1101538265456 |
10 | 314432012103 |
11 | 111393745630 |
12 | 50b32789b73 |
13 | 2385caa9b41 |
14 | 1130bb5399d |
15 | 82a46ca953 |
hex | 49359bbf47 |
314432012103 has 16 divisors (see below), whose sum is σ = 457736524032. Its totient is φ = 190406160000.
The previous prime is 314432012047. The next prime is 314432012143. The reversal of 314432012103 is 301210234413.
It is a happy number.
It is not a de Polignac number, because 314432012103 - 29 = 314432011591 is a prime.
It is a super-2 number, since 2×3144320121032 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (314432012143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3927163 + ... + 4006428.
It is an arithmetic number, because the mean of its divisors is an integer number (28608532752).
Almost surely, 2314432012103 is an apocalyptic number.
314432012103 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
314432012103 is a deficient number, since it is larger than the sum of its proper divisors (143304511929).
314432012103 is a wasteful number, since it uses less digits than its factorization.
314432012103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7934806.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 314432012103 its reverse (301210234413), we get a palindrome (615642246516).
The spelling of 314432012103 in words is "three hundred fourteen billion, four hundred thirty-two million, twelve thousand, one hundred three".
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