Base | Representation |
---|---|
bin | 11101010010001110… |
… | …110111110100001101 |
3 | 10000011102012002122001 |
4 | 131102032313310031 |
5 | 1003344231321141 |
6 | 22240110352301 |
7 | 2162136000466 |
oct | 352216676415 |
9 | 100142162561 |
10 | 31444401421 |
11 | 123765aa214 |
12 | 61167bb691 |
13 | 2c716bb8b4 |
14 | 17441d7d6d |
15 | c4083ea31 |
hex | 7523b7d0d |
31444401421 has 2 divisors, whose sum is σ = 31444401422. Its totient is φ = 31444401420.
The previous prime is 31444401383. The next prime is 31444401427. The reversal of 31444401421 is 12410444413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27116208900 + 4328192521 = 164670^2 + 65789^2 .
It is a cyclic number.
It is not a de Polignac number, because 31444401421 - 27 = 31444401293 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31444401421.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31444401427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15722200710 + 15722200711.
It is an arithmetic number, because the mean of its divisors is an integer number (15722200711).
Almost surely, 231444401421 is an apocalyptic number.
It is an amenable number.
31444401421 is a deficient number, since it is larger than the sum of its proper divisors (1).
31444401421 is an equidigital number, since it uses as much as digits as its factorization.
31444401421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 31444401421 its reverse (12410444413), we get a palindrome (43854845834).
The spelling of 31444401421 in words is "thirty-one billion, four hundred forty-four million, four hundred one thousand, four hundred twenty-one".
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