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31445113500301 is a prime number
BaseRepresentation
bin1110010011001011000101…
…10100011111001010001101
311010100010100000200211011111
413021211202310133022031
513110144043024002201
6150513404040452021
76423556140435214
oct711454264371215
9133303300624144
1031445113500301
11a023885886896
12363a334a7a011
1314713526168a7
147a9d4732c07b
15397e5d7e6b51
hex1c9962d1f28d

31445113500301 has 2 divisors, whose sum is σ = 31445113500302. Its totient is φ = 31445113500300.

The previous prime is 31445113500289. The next prime is 31445113500379. The reversal of 31445113500301 is 10300531154413.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21821034347401 + 9624079152900 = 4671299^2 + 3102270^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31445113500301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31445113500001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15722556750150 + 15722556750151.

It is an arithmetic number, because the mean of its divisors is an integer number (15722556750151).

Almost surely, 231445113500301 is an apocalyptic number.

It is an amenable number.

31445113500301 is a deficient number, since it is larger than the sum of its proper divisors (1).

31445113500301 is an equidigital number, since it uses as much as digits as its factorization.

31445113500301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 31445113500301 its reverse (10300531154413), we get a palindrome (41745644654714).

The spelling of 31445113500301 in words is "thirty-one trillion, four hundred forty-five billion, one hundred thirteen million, five hundred thousand, three hundred one".