Base | Representation |
---|---|
bin | 101101110001000010100… |
… | …101010010111111011010 |
3 | 102010122212202200212010020 |
4 | 231301002211102333122 |
5 | 403012011440242132 |
6 | 10404450330531310 |
7 | 443135565361422 |
oct | 55610245227732 |
9 | 12118782625106 |
10 | 3145033134042 |
11 | 100288a238a28 |
12 | 429641296b36 |
13 | 19a763082107 |
14 | ac312b6d482 |
15 | 56c2226452c |
hex | 2dc42952fda |
3145033134042 has 32 divisors (see below), whose sum is σ = 6312988584000. Its totient is φ = 1044528659328.
The previous prime is 3145033134031. The next prime is 3145033134043. The reversal of 3145033134042 is 2404313305413.
It is a junction number, because it is equal to n+sod(n) for n = 3145033133994 and 3145033134012.
It is not an unprimeable number, because it can be changed into a prime (3145033134043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2116573 + ... + 3281759.
It is an arithmetic number, because the mean of its divisors is an integer number (197280893250).
Almost surely, 23145033134042 is an apocalyptic number.
3145033134042 is an abundant number, since it is smaller than the sum of its proper divisors (3167955449958).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3145033134042 is a wasteful number, since it uses less digits than its factorization.
3145033134042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1166830.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 3145033134042 its reverse (2404313305413), we get a palindrome (5549346439455).
The spelling of 3145033134042 in words is "three trillion, one hundred forty-five billion, thirty-three million, one hundred thirty-four thousand, forty-two".
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