314520144121 has 2 divisors, whose sum is σ = 314520144122. Its totient is φ = 314520144120.

The previous prime is 314520144097. The next prime is 314520144137. The reversal of 314520144121 is 121441025413.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 308234825721 + 6285318400 = 555189^2 + 79280^2 .

It is an emirp because it is prime and its reverse (121441025413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314520144121 - 2¹¹ = 314520142073 is a prime.

It is a super-3 number, since 3×314520144121³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 314520144121.

It is not a weakly prime, because it can be changed into another prime (314520144721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157260072060 + 157260072061.

It is an arithmetic number, because the mean of its divisors is an integer number (157260072061).

Almost surely, 2^314520144121 is an apocalyptic number.

It is an amenable number.

314520144121 is a deficient number, since it is larger than the sum of its proper divisors (1).

314520144121 is an equidigital number, since it uses as much as digits as its factorization.

314520144121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 314520144121 its reverse (121441025413), we get a palindrome (435961169534).

The spelling of 314520144121 in words is "three hundred fourteen billion, five hundred twenty million, one hundred forty-four thousand, one hundred twenty-one".