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31452022105243 is a prime number
BaseRepresentation
bin1110010011010111111101…
…00110101110010010011011
311010100210011111110022111121
413021223332212232102123
513110302220124331433
6150520505352110111
76424222266551455
oct711537646562233
9133323144408447
1031452022105243
11a026800586a53
12363b742695337
131471bb39cc8cc
147aa400a972d5
153982150aac2d
hex1c9afe9ae49b

31452022105243 has 2 divisors, whose sum is σ = 31452022105244. Its totient is φ = 31452022105242.

The previous prime is 31452022105219. The next prime is 31452022105261. The reversal of 31452022105243 is 34250122025413.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31452022105243 is a prime.

It is a super-3 number, since 3×314520221052433 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31452022105199 and 31452022105208.

It is not a weakly prime, because it can be changed into another prime (31452022105043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15726011052621 + 15726011052622.

It is an arithmetic number, because the mean of its divisors is an integer number (15726011052622).

Almost surely, 231452022105243 is an apocalyptic number.

31452022105243 is a deficient number, since it is larger than the sum of its proper divisors (1).

31452022105243 is an equidigital number, since it uses as much as digits as its factorization.

31452022105243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 34.

The spelling of 31452022105243 in words is "thirty-one trillion, four hundred fifty-two billion, twenty-two million, one hundred five thousand, two hundred forty-three".