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31452553521133 is a prime number
BaseRepresentation
bin1110010011011000111100…
…10001111010011111101101
311010100211112112102001001121
413021230132101322133231
513110304312200134013
6150521034214140541
76424241411532103
oct711543621723755
9133324475361047
1031452553521133
11a026a53550638
12363b870651751
131471c69b34294
147aa4514a9c73
15398246a7c58d
hex1c9b1e47a7ed

31452553521133 has 2 divisors, whose sum is σ = 31452553521134. Its totient is φ = 31452553521132.

The previous prime is 31452553521097. The next prime is 31452553521157. The reversal of 31452553521133 is 33112535525413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26055583354089 + 5396970167044 = 5104467^2 + 2323138^2 .

It is a cyclic number.

It is not a de Polignac number, because 31452553521133 - 29 = 31452553520621 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31452553521133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31452553521833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15726276760566 + 15726276760567.

It is an arithmetic number, because the mean of its divisors is an integer number (15726276760567).

Almost surely, 231452553521133 is an apocalyptic number.

It is an amenable number.

31452553521133 is a deficient number, since it is larger than the sum of its proper divisors (1).

31452553521133 is an equidigital number, since it uses as much as digits as its factorization.

31452553521133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 810000, while the sum is 43.

The spelling of 31452553521133 in words is "thirty-one trillion, four hundred fifty-two billion, five hundred fifty-three million, five hundred twenty-one thousand, one hundred thirty-three".