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3145540244947 is a prime number
BaseRepresentation
bin101101110001100000110…
…011110001010111010011
3102010201012002220202111121
4231301200303301113103
5403014031300314242
610405012524023111
7443154263633032
oct55614063612723
912121162822447
103145540244947
11100301a511951
12429763091a97
1319a814156a39
14ac360256719
1556c51a34667
hex2dc60cf15d3

3145540244947 has 2 divisors, whose sum is σ = 3145540244948. Its totient is φ = 3145540244946.

The previous prime is 3145540244941. The next prime is 3145540244953. The reversal of 3145540244947 is 7494420455413.

3145540244947 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (3145540244941) and next prime (3145540244953).

It is an emirp because it is prime and its reverse (7494420455413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3145540244947 - 211 = 3145540242899 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3145540244894 and 3145540244903.

It is not a weakly prime, because it can be changed into another prime (3145540244941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572770122473 + 1572770122474.

It is an arithmetic number, because the mean of its divisors is an integer number (1572770122474).

Almost surely, 23145540244947 is an apocalyptic number.

3145540244947 is a deficient number, since it is larger than the sum of its proper divisors (1).

3145540244947 is an equidigital number, since it uses as much as digits as its factorization.

3145540244947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9676800, while the sum is 52.

The spelling of 3145540244947 in words is "three trillion, one hundred forty-five billion, five hundred forty million, two hundred forty-four thousand, nine hundred forty-seven".