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31465251355141 is a prime number
BaseRepresentation
bin1110010011110000100110…
…01000010011101000000101
311010102001022110121211201001
413021320103020103220011
513111011313321331031
6150530534212533301
76425201155406242
oct711702310235005
9133361273554631
1031465251355141
11a03137a10222a
123642215021231
13147321172a326
147aacd7a5a5c9
1539873b6e3861
hex1c9e13213a05

31465251355141 has 2 divisors, whose sum is σ = 31465251355142. Its totient is φ = 31465251355140.

The previous prime is 31465251355079. The next prime is 31465251355199. The reversal of 31465251355141 is 14155315256413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29788355852641 + 1676895502500 = 5457871^2 + 1294950^2 .

It is a cyclic number.

It is not a de Polignac number, because 31465251355141 - 233 = 31456661420549 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31465251355091 and 31465251355100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31465251358141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15732625677570 + 15732625677571.

It is an arithmetic number, because the mean of its divisors is an integer number (15732625677571).

Almost surely, 231465251355141 is an apocalyptic number.

It is an amenable number.

31465251355141 is a deficient number, since it is larger than the sum of its proper divisors (1).

31465251355141 is an equidigital number, since it uses as much as digits as its factorization.

31465251355141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1080000, while the sum is 46.

The spelling of 31465251355141 in words is "thirty-one trillion, four hundred sixty-five billion, two hundred fifty-one million, three hundred fifty-five thousand, one hundred forty-one".