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3147102430231 is a prime number
BaseRepresentation
bin101101110010111101111…
…011000010010000010111
3102010212012222102222211211
4231302331323002100113
5403030231210231411
610405431531042251
7443241063166054
oct55627573022027
912125188388754
103147102430231
111003751305871
12429b1a2a0387
1319aa029ac826
14ac46b90602b
1556ce3c64221
hex2dcbdec2417

3147102430231 has 2 divisors, whose sum is σ = 3147102430232. Its totient is φ = 3147102430230.

The previous prime is 3147102430181. The next prime is 3147102430267. The reversal of 3147102430231 is 1320342017413.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3147102430231 - 29 = 3147102429719 is a prime.

It is a super-2 number, since 2×31471024302312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3147102430193 and 3147102430202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3147102430271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1573551215115 + 1573551215116.

It is an arithmetic number, because the mean of its divisors is an integer number (1573551215116).

Almost surely, 23147102430231 is an apocalyptic number.

3147102430231 is a deficient number, since it is larger than the sum of its proper divisors (1).

3147102430231 is an equidigital number, since it uses as much as digits as its factorization.

3147102430231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 3147102430231 its reverse (1320342017413), we get a palindrome (4467444447644).

The spelling of 3147102430231 in words is "three trillion, one hundred forty-seven billion, one hundred two million, four hundred thirty thousand, two hundred thirty-one".