3149112803 has 2 divisors, whose sum is σ = 3149112804. Its totient is φ = 3149112802.

The previous prime is 3149112683. The next prime is 3149112817. The reversal of 3149112803 is 3082119413.

It is a strong prime.

It is an emirp because it is prime and its reverse (3082119413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3149112803 - 2¹² = 3149108707 is a prime.

It is a super-2 number, since 2×3149112803² = 19833822892037033618, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3149112803.

It is not a weakly prime, because it can be changed into another prime (3149112823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1574556401 + 1574556402.

It is an arithmetic number, because the mean of its divisors is an integer number (1574556402).

Almost surely, 2^3149112803 is an apocalyptic number.

3149112803 is a deficient number, since it is larger than the sum of its proper divisors (1).

3149112803 is an equidigital number, since it uses as much as digits as its factorization.

3149112803 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 32.

The square root of 3149112803 is about 56116.9564659382. The cubic root of 3149112803 is about 1465.7595727170.

The spelling of 3149112803 in words is "three billion, one hundred forty-nine million, one hundred twelve thousand, eight hundred three".