3149895253 has 2 divisors, whose sum is σ = 3149895254. Its totient is φ = 3149895252.

The previous prime is 3149895223. The next prime is 3149895257. The reversal of 3149895253 is 3525989413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2683032804 + 466862449 = 51798^2 + 21607^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3149895253 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3149895197 and 3149895206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3149895257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1574947626 + 1574947627.

It is an arithmetic number, because the mean of its divisors is an integer number (1574947627).

Almost surely, 2^3149895253 is an apocalyptic number.

It is an amenable number.

3149895253 is a deficient number, since it is larger than the sum of its proper divisors (1).

3149895253 is an equidigital number, since it uses as much as digits as its factorization.

3149895253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1166400, while the sum is 49.

The square root of 3149895253 is about 56123.9276334078. The cubic root of 3149895253 is about 1465.8809601971.

The spelling of 3149895253 in words is "three billion, one hundred forty-nine million, eight hundred ninety-five thousand, two hundred fifty-three".