3150050117 has 2 divisors, whose sum is σ = 3150050118. Its totient is φ = 3150050116.

The previous prime is 3150050107. The next prime is 3150050129. The reversal of 3150050117 is 7110500513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2572416961 + 577633156 = 50719^2 + 24034^2 .

It is a cyclic number.

It is not a de Polignac number, because 3150050117 - 2¹⁰ = 3150049093 is a prime.

It is a super-2 number, since 2×3150050117² = 19845631479223427378, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3150050092 and 3150050101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3150050107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575025058 + 1575025059.

It is an arithmetic number, because the mean of its divisors is an integer number (1575025059).

Almost surely, 2^3150050117 is an apocalyptic number.

It is an amenable number.

3150050117 is a deficient number, since it is larger than the sum of its proper divisors (1).

3150050117 is an equidigital number, since it uses as much as digits as its factorization.

3150050117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 525, while the sum is 23.

The square root of 3150050117 is about 56125.3072775553. The cubic root of 3150050117 is about 1465.9049830561.

The spelling of 3150050117 in words is "three billion, one hundred fifty million, fifty thousand, one hundred seventeen".