315024105041 has 2 divisors, whose sum is σ = 315024105042. Its totient is φ = 315024105040.

The previous prime is 315024105029. The next prime is 315024105043. The reversal of 315024105041 is 140501420513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 309140448016 + 5883657025 = 556004^2 + 76705^2 .

It is an emirp because it is prime and its reverse (140501420513) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 315024105041 - 2⁶ = 315024104977 is a prime.

It is a super-2 number, since 2×315024105041² (a number of 24 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 315024105043, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 315024105041.

It is not a weakly prime, because it can be changed into another prime (315024105043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157512052520 + 157512052521.

It is an arithmetic number, because the mean of its divisors is an integer number (157512052521).

Almost surely, 2^315024105041 is an apocalyptic number.

It is an amenable number.

315024105041 is a deficient number, since it is larger than the sum of its proper divisors (1).

315024105041 is an equidigital number, since it uses as much as digits as its factorization.

315024105041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 315024105041 its reverse (140501420513), we get a palindrome (455525525554).

The spelling of 315024105041 in words is "three hundred fifteen billion, twenty-four million, one hundred five thousand, forty-one".