Base | Representation |
---|---|
bin | 1001001010110010110… |
… | …01101101000101000001 |
3 | 1010010011011021022200221 |
4 | 10211121121231011001 |
5 | 20130141311214243 |
6 | 400420212143041 |
7 | 31521541156252 |
oct | 4453131550501 |
9 | 1103134238627 |
10 | 315032523073 |
11 | 111671712394 |
12 | 5107b907a81 |
13 | 23927324188 |
14 | 113677d0b29 |
15 | 82dc299bed |
hex | 495966d141 |
315032523073 has 2 divisors, whose sum is σ = 315032523074. Its totient is φ = 315032523072.
The previous prime is 315032523053. The next prime is 315032523077. The reversal of 315032523073 is 370325230513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 231368696064 + 83663827009 = 481008^2 + 289247^2 .
It is a cyclic number.
It is not a de Polignac number, because 315032523073 - 221 = 315030425921 is a prime.
It is not a weakly prime, because it can be changed into another prime (315032523077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157516261536 + 157516261537.
It is an arithmetic number, because the mean of its divisors is an integer number (157516261537).
Almost surely, 2315032523073 is an apocalyptic number.
It is an amenable number.
315032523073 is a deficient number, since it is larger than the sum of its proper divisors (1).
315032523073 is an equidigital number, since it uses as much as digits as its factorization.
315032523073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56700, while the sum is 34.
Adding to 315032523073 its reverse (370325230513), we get a palindrome (685357753586).
The spelling of 315032523073 in words is "three hundred fifteen billion, thirty-two million, five hundred twenty-three thousand, seventy-three".
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