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31504128001 is a prime number
BaseRepresentation
bin11101010101110010…
…101101100000000001
310000022120120112002121
4131111302231200001
51004010024044001
622250042444241
72163462445453
oct352562554001
9100276515077
1031504128001
11123a7293725
126132803681
132c80ba1278
14174c1042d3
15c45bdb6a1
hex755cad801

31504128001 has 2 divisors, whose sum is σ = 31504128002. Its totient is φ = 31504128000.

The previous prime is 31504127957. The next prime is 31504128013. The reversal of 31504128001 is 10082140513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31305994225 + 198133776 = 176935^2 + 14076^2 .

It is a cyclic number.

It is not a de Polignac number, because 31504128001 - 223 = 31495739393 is a prime.

It is a super-2 number, since 2×315041280012 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (31504128041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15752064000 + 15752064001.

It is an arithmetic number, because the mean of its divisors is an integer number (15752064001).

Almost surely, 231504128001 is an apocalyptic number.

It is an amenable number.

31504128001 is a deficient number, since it is larger than the sum of its proper divisors (1).

31504128001 is an equidigital number, since it uses as much as digits as its factorization.

31504128001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 31504128001 its reverse (10082140513), we get a palindrome (41586268514).

The spelling of 31504128001 in words is "thirty-one billion, five hundred four million, one hundred twenty-eight thousand, one".