Base | Representation |
---|---|
bin | 1110010100111001110010… |
… | …00110100000001111100111 |
3 | 11010112210201210000102112112 |
4 | 13022130321012200033213 |
5 | 13112132301014404112 |
6 | 151000553131511235 |
7 | 6431061643046465 |
oct | 712347106401747 |
9 | 133483653012475 |
10 | 31504543122407 |
11 | a0470022a8563 |
12 | 364995b8b851b |
13 | 1476b33b4a164 |
14 | 7acb84149835 |
15 | 39978ae2da22 |
hex | 1ca7391a03e7 |
31504543122407 has 2 divisors, whose sum is σ = 31504543122408. Its totient is φ = 31504543122406.
The previous prime is 31504543122389. The next prime is 31504543122427. The reversal of 31504543122407 is 70422134540513.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31504543122407 - 220 = 31504542073831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31504543122427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15752271561203 + 15752271561204.
It is an arithmetic number, because the mean of its divisors is an integer number (15752271561204).
Almost surely, 231504543122407 is an apocalyptic number.
31504543122407 is a deficient number, since it is larger than the sum of its proper divisors (1).
31504543122407 is an equidigital number, since it uses as much as digits as its factorization.
31504543122407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 403200, while the sum is 41.
The spelling of 31504543122407 in words is "thirty-one trillion, five hundred four billion, five hundred forty-three million, one hundred twenty-two thousand, four hundred seven".
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