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315062145413 is a prime number
BaseRepresentation
bin1001001010110110010…
…10101101000110000101
31010010020020000021220122
410211123022231012011
520130221402123123
6400423151111325
731522351022621
oct4453312550605
91103206007818
10315062145413
11111687405064
1251089812545
13239304c62a2
141136b702181
1582deb9bbc8
hex495b2ad185

315062145413 has 2 divisors, whose sum is σ = 315062145414. Its totient is φ = 315062145412.

The previous prime is 315062145389. The next prime is 315062145467. The reversal of 315062145413 is 314541260513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 309850316164 + 5211829249 = 556642^2 + 72193^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-315062145413 is a prime.

It is a super-3 number, since 3×3150621454133 (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (315062145313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157531072706 + 157531072707.

It is an arithmetic number, because the mean of its divisors is an integer number (157531072707).

Almost surely, 2315062145413 is an apocalyptic number.

It is an amenable number.

315062145413 is a deficient number, since it is larger than the sum of its proper divisors (1).

315062145413 is an equidigital number, since it uses as much as digits as its factorization.

315062145413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 315062145413 in words is "three hundred fifteen billion, sixty-two million, one hundred forty-five thousand, four hundred thirteen".