Base | Representation |
---|---|
bin | 101101110110010101111… |
… | …101101111000011101001 |
3 | 102011012120120202001201102 |
4 | 231312111331233003221 |
5 | 403110142104013211 |
6 | 10411231330331145 |
7 | 443426644521356 |
oct | 55662575570351 |
9 | 12135516661642 |
10 | 3150727016681 |
11 | 1005241297262 |
12 | 42a770129ab5 |
13 | 19b15c8ba83a |
14 | ac6d305562d |
15 | 56e57080a3b |
hex | 2dd95f6f0e9 |
3150727016681 has 2 divisors, whose sum is σ = 3150727016682. Its totient is φ = 3150727016680.
The previous prime is 3150727016641. The next prime is 3150727016707. The reversal of 3150727016681 is 1866107270513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2963338459225 + 187388557456 = 1721435^2 + 432884^2 .
It is a cyclic number.
It is not a de Polignac number, because 3150727016681 - 214 = 3150727000297 is a prime.
It is a super-2 number, since 2×31507270166812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3150727016641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575363508340 + 1575363508341.
It is an arithmetic number, because the mean of its divisors is an integer number (1575363508341).
Almost surely, 23150727016681 is an apocalyptic number.
It is an amenable number.
3150727016681 is a deficient number, since it is larger than the sum of its proper divisors (1).
3150727016681 is an equidigital number, since it uses as much as digits as its factorization.
3150727016681 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 423360, while the sum is 47.
The spelling of 3150727016681 in words is "three trillion, one hundred fifty billion, seven hundred twenty-seven million, sixteen thousand, six hundred eighty-one".
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