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315114053152 = 2513903708287
BaseRepresentation
bin1001001010111100100…
…00101101111000100000
31010010100211200110221111
410211132100231320200
520130323144200102
6400432243433104
731523551154263
oct4453620557040
91103324613844
10315114053152
11111703739118
12510a3085794
132393b19bb22
1411374574cda
1582e4501cd7
hex495e42de20

315114053152 has 24 divisors (see below), whose sum is σ = 620426290176. Its totient is φ = 157545471552.

The previous prime is 315114053129. The next prime is 315114053179. The reversal of 315114053152 is 251350411513.

It is a super-2 number, since 2×3151140531522 (a number of 24 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90753 + ... + 799039.

It is an arithmetic number, because the mean of its divisors is an integer number (25851095424).

Almost surely, 2315114053152 is an apocalyptic number.

315114053152 is a gapful number since it is divisible by the number (32) formed by its first and last digit.

It is an amenable number.

315114053152 is a deficient number, since it is larger than the sum of its proper divisors (305312237024).

315114053152 is a wasteful number, since it uses less digits than its factorization.

315114053152 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 722200 (or 722192 counting only the distinct ones).

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 315114053152 its reverse (251350411513), we get a palindrome (566464464665).

The spelling of 315114053152 in words is "three hundred fifteen billion, one hundred fourteen million, fifty-three thousand, one hundred fifty-two".

Divisors: 1 2 4 8 16 32 13903 27806 55612 111224 222448 444896 708287 1416574 2833148 5666296 11332592 22665184 9847314161 19694628322 39389256644 78778513288 157557026576 315114053152